x^2+4y=2(3x-6-x)+x^2

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Solution for x^2+4y=2(3x-6-x)+x^2 equation:


Simplifying
x2 + 4y = 2(3x + -6 + -1x) + x2

Reorder the terms:
x2 + 4y = 2(-6 + 3x + -1x) + x2

Combine like terms: 3x + -1x = 2x
x2 + 4y = 2(-6 + 2x) + x2
x2 + 4y = (-6 * 2 + 2x * 2) + x2
x2 + 4y = (-12 + 4x) + x2

Add '-1x2' to each side of the equation.
x2 + -1x2 + 4y = -12 + 4x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 + 4y = -12 + 4x + x2 + -1x2
4y = -12 + 4x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
4y = -12 + 4x + 0
4y = -12 + 4x

Solving
4y = -12 + 4x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '4'.
y = -3 + x

Simplifying
y = -3 + x

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